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3x^2-2x-280=0
a = 3; b = -2; c = -280;
Δ = b2-4ac
Δ = -22-4·3·(-280)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-58}{2*3}=\frac{-56}{6} =-9+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+58}{2*3}=\frac{60}{6} =10 $
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